GroupAnagrams
Published at 2022-03-13
class Solution:
def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
answer = []
dic = {}
for s in strs:
sort = ''.join(sorted(s))
if sort not in dic:
dic[sort] = len(dic)
answer.append([])
answer[dic[sort]].append(s)
return answer /**
* @param {string[]} strs
* @return {string[][]}
*/
var groupAnagrams = function(strs) {
const map = {};
for(const s of strs){
const sortedStr = [...s].sort();
map[sortedStr] = map[sortedStr] ? [...map[sortedStr], s] : [s];
}
return Object.values(map); // 객체의 값만 뽑기
};